derivative (x^2-4x)/(x+1)

Lösung

ableitung von

\frac{x ^{2} - 4 x}{x + 1}

\frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 4 x}{x + 1})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 4 x ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x ^{2} - 4 x )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

\frac{d}{d x} (x + 1) = 1

= \frac{( 2 x - 4 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 4 x )}{( x + 1 ) ^{2}}

Vereinfache

\frac{( 2 x - 4 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 4 x )}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

y^{^{''}} + 2 y^{^{'}} = sin (x)

\frac{d}{d x} (sec^{2} (3 x) \cdot 3)

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