What is (\partial)/(\partial x)(4x^3y^2-2) ?

The answer to (\partial)/(\partial x)(4x^3y^2-2) is 12x^2y^2

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(\partial)/(\partial x)(4x^3y^2-2)

\frac{\partial}{\partial x} (4 x^{3} y^{2} - 2)

12 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (4 x^{3} y^{2} - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3} y^{2}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (4 x^{3} y^{2}) = 12 y^{2} x^{2}

\frac{\partial}{\partial x} (2) = 0

= 12 y^{2} x^{2} - 0

Simplify

= 12 x^{2} y^{2}

d er i v a t i v e y = x^{4} - 2 x^{3} - 9

\int (x - 1) d x

x \to 0 lim (\frac{x}{1 - x})

\frac{\partial}{\partial x} (sin (x - 3 y))

\int_{- 1}^{0} (x + 2)^{13} d x

What is (\partial)/(\partial x)(4x^3y^2-2) ?
The answer to (\partial)/(\partial x)(4x^3y^2-2) is 12x^2y^2