(\partial)/(\partial x)(1+xy^2-2z^2)

Lösung

\frac{\partial}{\partial x} (1 + x y^{2} - 2 z^{2})

y^{2}

Schritte zur Lösung

\frac{\partial}{\partial x} (1 + x y^{2} - 2 z^{2})

Behandle

y, z

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x y^{2}) - \frac{\partial}{\partial x} (2 z^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

\frac{\partial}{\partial x} (2 z^{2}) = 0

= 0 + y^{2} - 0

Vereinfache

= y^{2}

\int \frac{e ^{x}}{e ^{x}} d x

d er i v a t i v e \frac{1}{y ^{2}} - \frac{9}{y ^{4}} (y + 3 y^{3})

n = 1 \sum \infty \frac{10 n}{n + 1}

\frac{d}{d x} (\frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}})

\int - 2 x^{3} (- 5 x^{2} - x + 12) d x