What is the integral from 0 to 3 of c*(3-x) ?

The integral from 0 to 3 of c*(3-x) is 9/2 c

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integral from 0 to 3 of c*(3-x)

\int_{0}^{3} c \cdot (3 - x) d x

\frac{9}{2} c

Solution steps

\int_{0}^{3} c (3 - x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= c \cdot \int_{0}^{3} 3 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= c (\int_{0}^{3} 3 d x - \int_{0}^{3} x d x)

\int_{0}^{3} 3 d x = 9

\int_{0}^{3} x d x = \frac{9}{2}

= c (9 - \frac{9}{2})

Join

9 - \frac{9}{2} : \frac{9}{2}

= \frac{9}{2} c

x \to 0 lim (x - 6)

d er i v a t i v e \frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}}

l a pl a ce t r an s f or m t^{2}

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{- \frac{1}{2}})

d er i v a t i v e 1 + e^{0.5499 - 0.09 x}

What is the integral from 0 to 3 of c*(3-x) ?
The integral from 0 to 3 of c*(3-x) is 9/2 c