d/(dt)(1+cos(t))

解答

\frac{d}{d t} (1 + cos (t))

- sin (t)

求解步骤

\frac{d}{d t} (1 + cos (t))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (cos (t))

\frac{d}{d t} (1) = 0

\frac{d}{d t} (cos (t)) = - sin (t)

= 0 - sin (t)

化简

= - sin (t)

- 2 y^{^{'}} + \frac{4 y}{x} = \frac{y ^{3}}{x}

\frac{d}{d t} (\frac{1}{t ^{2}})

\int \frac{5 x - 1}{( 2 x + 1 ) ( x - 1 )} d x

\frac{d y}{d t} = k y (100 - y)

\frac{d}{d x} (lo g_{4} ((x^{2} + 2 x)^{3}))