xy^'=y+x,y(1)=1

Lösung

x y^{^{'}} = y + x, y (1) = 1

y = x ln (x) + x

Schritte zur Lösung

x y^{'} (x) = y + x

Solve linear ODE:

y = x ln (x) + x

y = x ln (x) + x

l a pl a ce t r an s f or m 10 ln (0.5) x

\int x^{3} cos (4 x) d x

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