derivative (3x^6+4x^3)^4

Lösung

ableitung von

(3 x^{6} + 4 x^{3})^{4}

4 (3 x^{6} + 4 x^{3})^{3} (18 x^{5} + 12 x^{2})

Schritte zur Lösung

\frac{d}{d x} ((3 x^{6} + 4 x^{3})^{4})

Wende die Kettenregel an:

4 (3 x^{6} + 4 x^{3})^{3} \frac{d}{d x} (3 x^{6} + 4 x^{3})

= 4 (3 x^{6} + 4 x^{3})^{3} \frac{d}{d x} (3 x^{6} + 4 x^{3})

\frac{d}{d x} (3 x^{6} + 4 x^{3}) = 18 x^{5} + 12 x^{2}

= 4 (3 x^{6} + 4 x^{3})^{3} (18 x^{5} + 12 x^{2})

\int_{- \infty}^{1} - e^{x} d x

in v erse l a pl a ce \frac{6 ( s + 1 )}{s ^{2} ( s + 1 )}

\frac{\partial}{\partial x} (arcsin (2 x))

a re a x^{\frac{1}{2}}, x^{2}

d er i v a t i v e y = \frac{9}{x} + 2 sin (x)