What is the derivative of-4x^4+8x^3 ?

The derivative of-4x^4+8x^3 is -16x^3+24x^2

What is the first derivative of-4x^4+8x^3 ?

The first derivative of-4x^4+8x^3 is -16x^3+24x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (- 4 x^{4} + 8 x^{3})

- 16 x^{3} + 24 x^{2}

Solution steps

\frac{d}{d x} (- 4 x^{4} + 8 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{4}) + \frac{d}{d x} (8 x^{3})

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

= - 16 x^{3} + 24 x^{2}

in v erse l a pl a ce \frac{( 3 s + 1 )}{s ( s + 2 )}

y^{^{'}} - \frac{6}{x} y = \frac{( y ^{5} )}{x ^{18}}, y (1) = 1

d er i v a t i v e g (x) = 3 (5 - 7 x)^{5}

\frac{d}{d x} (sin (\frac{π}{4}))

\int \frac{7 e ^{2 t}}{1 + e ^{4 t}} d t

What is the derivative of-4x^4+8x^3 ?
The derivative of-4x^4+8x^3 is -16x^3+24x^2
What is the first derivative of-4x^4+8x^3 ?
The first derivative of-4x^4+8x^3 is -16x^3+24x^2