ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

(\partial)/(\partial y)(2x-3yz)

解

\frac{\partial}{\partial y} (2 x - 3 yz)

解

- 3 z

解答ステップ

\frac{\partial}{\partial y} (2 x - 3 yz)

x, z

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (3 yz)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (3 yz) = 3 z

= 0 - 3 z

簡素化

= - 3 z

人気の例

d/(d{r)}((200{r}({r}+2))/((2+3{r))^2})

\frac{d}{d r} (\frac{200 r ( r + 2 )}{( 2 + 3 r ) ^{2}})

tangent y=sqrt(9-10x),\at x=-1

t an g e n t y = 9 - 10 x, at x = - 1

derivative of 2xy^3

\frac{d}{d x} (2 x y^{3})

(\partial)/(\partial y)(e^{sin(x+y)})

\frac{\partial}{\partial y} (e^{s i n (x + y)})

tangent f(x)=1+4csc(x),\at x=-pi/3

t an g e n t f (x) = 1 + 4 csc (x), at x = - \frac{π}{3}