What is (\partial)/(\partial x)(sin(3x)cos(2y)) ?

The answer to (\partial)/(\partial x)(sin(3x)cos(2y)) is cos(2y)cos(3x)*3

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(\partial)/(\partial x)(sin(3x)cos(2y))

\frac{\partial}{\partial x} (sin (3 x) cos (2 y))

cos (2 y) cos (3 x) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x) cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 y) \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= cos (2 y) cos (3 x) \cdot 3

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\int \frac{x}{3 x + 12} d x

What is (\partial)/(\partial x)(sin(3x)cos(2y)) ?
The answer to (\partial)/(\partial x)(sin(3x)cos(2y)) is cos(2y)cos(3x)*3