What is the d/(dy)(cos(2y)) ?

The d/(dy)(cos(2y)) is -sin(2y)*2

What is the first d/(dy)(cos(2y)) ?

The first d/(dy)(cos(2y)) is -sin(2y)*2

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\frac{d}{d y} (cos (2 y))

- sin (2 y) \cdot 2

Solution steps

\frac{d}{d y} (cos (2 y))

Apply the chain rule:

- sin (2 y) \frac{d}{d y} (2 y)

= - sin (2 y) \frac{d}{d y} (2 y)

\frac{d}{d y} (2 y) = 2

= - sin (2 y) \cdot 2

x \to 0 - lim (5 x^{3} - 7 x^{2} + 2^{x} - 2)

\int \frac{1}{t ^{2} - 6 t + 34} d t

t an g e n t f (x) = 8 (x - \frac{1}{x})^{2}

\int sin (x^{3}) d x

\frac{d}{d x} (6 sin (6 x))