integral from 4 to 14 of 16+(4-x)^2

Lösung

\int_{4}^{14} 16 + (4 - x)^{2} d x

\frac{1480}{3}

Dezimale

493.33333 \dots

Schritte zur Lösung

\int_{4}^{14} 16 + (4 - x)^{2} d x

Vereinfache

16 + (4 - x)^{2} : x^{2} - 8 x + 32

= \int_{4}^{14} x^{2} - 8 x + 32 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{14} x^{2} d x - \int_{4}^{14} 8 x d x + \int_{4}^{14} 32 d x

\int_{4}^{14} x^{2} d x = \frac{2680}{3}

\int_{4}^{14} 8 x d x = 720

\int_{4}^{14} 32 d x = 320

= \frac{2680}{3} - 720 + 320

Vereinfache

\frac{2680}{3} - 720 + 320 : \frac{1480}{3}

= \frac{1480}{3}

y^{^{'}} = y + 2 e^{- e}

\int (x sin (x y)) d x

\frac{d}{d t} (\frac{t}{1 + t ^{2}})

y^{^{'}} + 3.25 y = 26

d er i v a t i v e f (x) = x^{6 x}