derivative f(x)=-5x^2+2x-6

Lösung

ableitung von

f (x) = - 5 x^{2} + 2 x - 6

- 10 x + 2

Schritte zur Lösung

\frac{d}{d x} (- 5 x^{2} + 2 x - 6)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (6)

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (6) = 0

= - 10 x + 2 - 0

Vereinfache

= - 10 x + 2

x \to 0 + lim (\frac{∣ x - 0 ∣}{0 - x})

\int_{2}^{\infty} x e^{- 4 x} d x

\int 3 e^{2 x^{3} + 3 x^{2} - 9} (x^{2} + x) d x

\frac{\partial}{\partial y} (e^{x^{2} + y^{2} - 2})

d er i v a t i v e 3 x^{2} + 2