integral of x^2-16x

Lösung

\int x^{2} - 16 x d x

\frac{x ^{3}}{3} - 8 x^{2} + C

Schritte zur Lösung

\int x^{2} - 16 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 16 x d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 16 x d x = 8 x^{2}

= \frac{x ^{3}}{3} - 8 x^{2}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 8 x^{2} + C

l a pl a ce t r an s f or m t^{2} + 6 t - 3

t an g e n t f (x) = 3 - 4 x^{2}, - 61, at x = 4

\int 2 x^{3} + 4 d x

x \to 8 - lim (\frac{x + 7}{x + 8})

\int \frac{1}{4 - ( x - 1 ) ^{2}} d x