What is the tangent of y=3x^3-x^2+5,(2,25) ?

The tangent of y=3x^3-x^2+5,(2,25) is y=32x-39

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tangent of y=3x^3-x^2+5,(2,25)

tangent of

y = 3 x^{3} - x^{2} + 5, (2, 25)

y = 32 x - 39

Solution steps

Find the slope of

y = 3 x^{3} - x^{2} + 5 : \frac{d y}{d x} = 9 x^{2} - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 32

Find the line with slope m=

32

and passing through

(2, 25) : y = 32 x - 39

y = 32 x - 39

\int_{1}^{\infty} \frac{1}{x ^{4}} d x

\int e^{(x + 1)^{2}} (x + 1) d x

t an g e n t f (x) = \frac{1}{x} - 2, (- 1, - 3)

d er i v a t i v e g (x) = x^{3} \cdot e^{x}

\int_{0}^{\frac{π}{6}} (3 sec^{2} (x)) d x

What is the tangent of y=3x^3-x^2+5,(2,25) ?
The tangent of y=3x^3-x^2+5,(2,25) is y=32x-39