What is the sum from n=0 to infinity of 2^n ?

The sum from n=0 to infinity of 2^n is diverges

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sum from n=0 to infinity of 2^n

n = 0 \sum \infty 2^{n}

diverges

Solution steps

n = 0 \sum \infty 2^{n}

Apply Series Geometric Test:

diverges

= diverges

d er i v a t i v e (- x^{2} - 2 x - 2)^{3}

\int (4 x + 2)^{2} d x

x \to 0 lim (\frac{sin ( x + π )}{x})

\frac{d y}{d x} = - \frac{1 + y ^{2}}{1 + x ^{2}}

\frac{d}{d t} (1 - 2 cos (t))

What is the sum from n=0 to infinity of 2^n ?
The sum from n=0 to infinity of 2^n is diverges