What is the integral from-1 to 1 of (t^3-9t) ?

The integral from-1 to 1 of (t^3-9t) is 0

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integral from-1 to 1 of (t^3-9t)

\int_{- 1}^{1} (t^{3} - 9 t) d t

0

Solution steps

\int_{- 1}^{1} t^{3} - 9 t d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t^{3} - 9 t :

Odd

= 0

t an g e n t \frac{2}{x - 6}

y^{^{'}} - 2 x y = x y^{2}

n \to \infty lim (\frac{1}{2 n})

\frac{d}{d x} (5 x cos (\frac{x}{5}))

\int_{6}^{7} \frac{x}{x ^{2} + 6 x + 13} d x

What is the integral from-1 to 1 of (t^3-9t) ?
The integral from-1 to 1 of (t^3-9t) is 0