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人気のある微分積分 >

integral from 1 to 2 of (|x+1|+2)

解

\int_{1}^{2} (∣ x + 1 ∣ + 2) d x

解

\frac{9}{2}

+1

十進法表記

4.5

解答ステップ

\int_{1}^{2} ∣ x + 1 ∣ + 2 d x

絶対数を排除する

= \int_{1}^{2} x + 1 + 2 d x

簡素化

= \int_{1}^{2} x + 3 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d x + \int_{1}^{2} 3 d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 3 d x = 3

= \frac{3}{2} + 3

簡素化

\frac{3}{2} + 3 : \frac{9}{2}

= \frac{9}{2}

グラフ

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