-y^'+(3y)/x =(y^2)/x

Lösung

- y^{^{'}} + \frac{3 y}{x} = \frac{y ^{2}}{x}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

Schritte zur Lösung

- y^{'} (x) + \frac{3 y}{x} = \frac{y ^{2}}{x}

Solve separable ODE:

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

\frac{d}{d x} (\frac{7 x ^{2} + 3 x + 7}{x})

x \to 0 + lim (7 (\frac{1}{x} - cot (x)))

d er i v a t i v e y = x^{x}

x \to + π + lim (csc (x))

\frac{d}{d x} ((x - 42)^{2} - 3 x ln ((x - 100)^{2}))