laplacetransform tsin(0.32t)

Lösung

laplace transformation

t sin (0.32 t)

\frac{0.64 s}{( s ^{2} + 0.1024 ) ^{2}}

Schritte zur Lösung

L {t sin (0.32 t)}

Wende Laplace-Transformationstabelle an:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

Für

t sin (0.32 t) : f (t) = sin (0.32 t), k = 1

= (- 1)^{1} \frac{d}{d s} (L {sin (0.32 t)})

L {sin (0.32 t)} : \frac{0.32}{s ^{2} + 0.1024}

\frac{d}{d s} (\frac{0.32}{s ^{2} + 0.1024}) = - \frac{0.64 s}{( s ^{2} + 0.1024 ) ^{2}}

= (- 1)^{1} (- \frac{0.64 s}{( s ^{2} + 0.1024 ) ^{2}})

= \frac{0.64 s}{( s ^{2} + 0.1024 ) ^{2}}

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