y^'-4/x y=4x^5

解答

y^{^{'}} - \frac{4}{x} y = 4 x^{5}

y = 2 x^{6} + c_{1} x^{4}

求解步骤

y^{'} (x) - \frac{4}{x} y = 4 x^{5}

求解线性方程:

y = 2 x^{6} + c_{1} x^{4}

y = 2 x^{6} + c_{1} x^{4}

\frac{d}{d x} (\frac{x}{csch ( x )})

\int 30 x \cdot (x + 1)^{4} d x

\frac{d}{d x} (\frac{2 x}{( 1 + x ^{2} ) ^{2}})

\int \frac{x ^{4}}{x ^{4} - 16} d x

y^{^{''}} + 9 y = 2 cos (3 x) + 3 sin (3 x)