y^{''}+(10+5)y=((10-5))/2

解答

y^{^{''}} + (10 + 5) y = \frac{( 10 - 5 )}{2}

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

求解步骤

y^{''} (t) + (10 + 5) y = \frac{( 10 - 5 )}{2}

求解线性方程:

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

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