derivative of 3x+x^2-3x^3-x^4

Lösung

\frac{d}{d x} (3 x + x^{2} - 3 x^{3} - x^{4})

3 + 2 x - 9 x^{2} - 4 x^{3}

Schritte zur Lösung

\frac{d}{d x} (3 x + x^{2} - 3 x^{3} - x^{4})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (x^{4})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 3 + 2 x - 9 x^{2} - 4 x^{3}

\frac{d}{d x} (x - 10 3 x)

\frac{\partial}{\partial x} (x^{2} + y^{2} - x y)

\int 2 e^{x} + 8 x^{3} + 6 x d x

\frac{d y}{d x} + 3 y = 8

\int_{2}^{3} \frac{9}{3 - x} d x