derivative y=(x^3)/3+1/(4x)

Lösung

ableitung von

y = \frac{x ^{3}}{3} + \frac{1}{4 x}

x^{2} - \frac{1}{4 x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{1}{4 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (\frac{1}{4 x})

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{1}{4 x}) = - \frac{1}{4 x ^{2}}

= x^{2} - \frac{1}{4 x ^{2}}

\int_{- 1}^{2} 2 x 2 x^{2} + 3 d x

\int_{1}^{4} (\frac{1}{x ^{3}} + x) d x

\frac{\partial}{\partial x} (cos (x + 4 y))

d er i v a t i v e 200 + \frac{7}{x} + \frac{x ^{2}}{7}

\frac{d}{d x} (- 4 sin (4 x))