What is the limit as x approaches infinity of-0.5^x ?

The limit as x approaches infinity of-0.5^x is 0

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limit as x approaches infinity of-0.5^x

x \to \infty lim (- 0. 5^{x})

0

Solution steps

x \to \infty lim (- 0. 5^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (0. 5^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = 0, 0 < a < 1

= - 0

Simplify

= 0

d er i v a t i v e ln (sin (4 x))

\frac{\partial}{\partial x} (x y z^{2})

\frac{d}{d y} (x y + y x^{2} + y^{2})

\frac{d}{d x} (2190 \cdot e^{- 0.3 x})

x \to \frac{π}{2} + lim (3 e^{t a n (x)})

What is the limit as x approaches infinity of-0.5^x ?
The limit as x approaches infinity of-0.5^x is 0