What is the integral of-\sqrt[4]{x} ?

The integral of-\sqrt[4]{x} is -4/5 x^{5/4}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of-\sqrt[4]{x}

\int - 4 x d x

- \frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

\int - 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int 4 x d x

Apply the Power Rule

= - \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= - \frac{4}{5} x^{\frac{5}{4}} + C

\frac{d y}{d x} = \frac{y ( - 2 x + 4 )}{( x ^{2} + 1 ) ( x - 1 ) ^{2}}

d er i v a t i v e 3 arccos (\frac{x}{2})

\int \frac{( x - 2 ) ( x + 3 )}{x ^{2}} d x

\frac{d}{d x} (72 cos (x))

e x t re m e f (w) = \frac{w}{w + \frac{d}{w}}

What is the integral of-\sqrt[4]{x} ?
The integral of-\sqrt[4]{x} is -4/5 x^{5/4}+C