What is the derivative of sqrt(2x^2) ?

The derivative of sqrt(2x^2) is square root of 2

What is the first derivative of sqrt(2x^2) ?

The first derivative of sqrt(2x^2) is square root of 2

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\frac{d}{d x} (2 x^{2})

2

Decimal

1.41421 \dots

Solution steps

\frac{d}{d x} (2 x^{2})

Apply the chain rule:

\frac{1}{2 2 x ^{2}} \frac{d}{d x} (2 x^{2})

= \frac{1}{2 2 x ^{2}} \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (2 x^{2}) = 4 x

= \frac{1}{2 2 x ^{2}} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2}} \cdot 4 x : 2

= 2

\int sec (x) \cdot tan^{2} (x) d x

d er i v a t i v e 3 x e^{- 2 x}

d er i v a t i v e G (r) = r + 7 r

d er i v a t i v e x \cdot x

\int 5 + 8 x d x

What is the derivative of sqrt(2x^2) ?
The derivative of sqrt(2x^2) is square root of 2
What is the first derivative of sqrt(2x^2) ?
The first derivative of sqrt(2x^2) is square root of 2