What is the integral from 0 to 2 of (x^2)^2 ?

The integral from 0 to 2 of (x^2)^2 is 32/5

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integral from 0 to 2 of (x^2)^2

\int_{0}^{2} (x^{2})^{2} d x

\frac{32}{5}

Decimal

6.4

Solution steps

\int_{0}^{2} (x^{2})^{2} d x

Simplify

(x^{2})^{2} : x^{4}

= \int_{0}^{2} x^{4} d x

Apply the Power Rule

= [\frac{x ^{5}}{5}]_{0}^{2}

Compute the boundaries:

\frac{32}{5}

= \frac{32}{5}

x \to 0 lim (\frac{1}{1 - e ^{x}} - \frac{1}{x})

\int e^{x^{2}} x d x

x \to - 5 + lim (\frac{∣ x - 5 ∣}{x - 5})

\frac{d}{d x} (9 cos (x) - cos (9 x))

x \to 0 lim (\frac{1}{1 + x})

What is the integral from 0 to 2 of (x^2)^2 ?
The integral from 0 to 2 of (x^2)^2 is 32/5