derivative 0.5cos(2pit)

解答

导数

0.5 cos (2 π t)

- 3.14159 \dots sin (6.28318 \dots t)

求解步骤

\frac{d}{d t} (0.5 cos (2 π t))

化简

0.5 cos (2 π t) : 0.5 cos (6.28318 \dots t)

= \frac{d}{d t} (0.5 cos (6.28318 \dots t))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.5 \frac{d}{d t} (cos (6.28318 \dots t))

使用连锁律:

- sin (6.28318 \dots t) \frac{d}{d t} (6.28318 \dots t)

= - sin (6.28318 \dots t) \frac{d}{d t} (6.28318 \dots t)

\frac{d}{d t} (6.28318 \dots t) = 6.28318 \dots

= 0.5 (- sin (6.28318 \dots t) \cdot 6.28318 \dots)

化简

= - 3.14159 \dots sin (6.28318 \dots t)

\frac{\partial}{\partial x} (4 x y^{3} + 1)

f (x) = \frac{1}{x} - ln (x)

n = 1 \sum \infty \frac{7 ^{n}}{n !}

t an g e n t f (x) = π (10 - \frac{π}{3}) x^{2}, at x = 3

\frac{d}{d x} (\frac{18}{x ^{3}})