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Popular Calculus >

integral from-1 to 1 of x^2-x^4

Solution

\int_{- 1}^{1} x^{2} - x^{4} d x

Solution

\frac{4}{15}

+1

Decimal

0.26666 \dots

Solution steps

\int_{- 1}^{1} x^{2} - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x - \int_{- 1}^{1} x^{4} d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} x^{4} d x = \frac{2}{5}

= \frac{2}{3} - \frac{2}{5}

Simplify

\frac{2}{3} - \frac{2}{5} : \frac{4}{15}

= \frac{4}{15}

Graph

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integral of (8x^2-4x+7)/(4x^3+x^2+4x+1)

\int \frac{8 x ^{2} - 4 x + 7}{4 x ^{3} + x ^{2} + 4 x + 1} d x

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x^2-x^4 ?
The integral from-1 to 1 of x^2-x^4 is 4/15