(\partial)/(\partial y)(e^{xy}+2x-5y)

解答

\frac{\partial}{\partial y} (e^{x y} + 2 x - 5 y)

e^{x y} x - 5

求解步骤

\frac{\partial}{\partial y} (e^{x y} + 2 x - 5 y)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x y}) + \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (5 y)

\frac{\partial}{\partial y} (e^{x y}) = e^{x y} x

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (5 y) = 5

= e^{x y} x + 0 - 5

化简

= e^{x y} x - 5

t an g e n t y = 2 x^{3} - 5 x + 1, (1, - 2)

\int x 1 - x^{2} d x

t an g e n t f (x) = \frac{10 x}{1 + x ^{2}}, (3, 3)

x^{5} + y^{4} x^{6} + 5 y^{^{'}} = 0

x \to + 1 + lim (ln (3 x^{2} - x - 2))