derivative sqrt(ln(7x+9))

Lösung

ableitung von

ln (7 x + 9)

\frac{7}{2 ln ( 7 x + 9 ) ( 7 x + 9 )}

Schritte zur Lösung

\frac{d}{d x} (ln (7 x + 9))

Wende die Kettenregel an:

\frac{1}{2 ln ( 7 x + 9 )} \frac{d}{d x} (ln (7 x + 9))

= \frac{1}{2 ln ( 7 x + 9 )} \frac{d}{d x} (ln (7 x + 9))

\frac{d}{d x} (ln (7 x + 9)) = \frac{7}{7 x + 9}

= \frac{1}{2 ln ( 7 x + 9 )} \cdot \frac{7}{7 x + 9}

Vereinfache

\frac{1}{2 ln ( 7 x + 9 )} \cdot \frac{7}{7 x + 9} : \frac{7}{2 ln ( 7 x + 9 ) ( 7 x + 9 )}

= \frac{7}{2 ln ( 7 x + 9 ) ( 7 x + 9 )}

\int x^{2} 3^{x} d x

\int x^{2} + x + 3 d x

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{7}{x})

\frac{d}{d x} (\frac{3 ( 9 ^{x} )}{x ^{5}})

\int \frac{1}{x ^{5}} sin (\frac{1}{x ^{4}}) d x