What is (\partial)/(\partial z)(ln(z)) ?

The answer to (\partial)/(\partial z)(ln(z)) is 1/z

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(\partial)/(\partial z)(ln(z))

\frac{\partial}{\partial z} (ln (z))

\frac{1}{z}

Solution steps

\frac{\partial}{\partial z} (ln (z))

Apply the common derivative:

\frac{\partial}{\partial z} (ln (z)) = \frac{1}{z}

= \frac{1}{z}

d er i v a t i v e f (x) = cos (x) + sin (x)

\frac{d x}{d y} = 4 (x^{2} + 1), x (\frac{π}{4}) = 1

\int_{1}^{6} \frac{x ^{2} + 5}{7 x - x ^{2}} d x

l a pl a ce t r an s f or m \frac{cos ( 7 t )}{e ^{5 t}}

x \frac{d y}{d x} + y = y^{2} x^{2} ln (x)

What is (\partial)/(\partial z)(ln(z)) ?
The answer to (\partial)/(\partial z)(ln(z)) is 1/z