What is the tangent of f(x)=tan(3x),\at x= pi/9 ?

The tangent of f(x)=tan(3x),\at x= pi/9 is y=12x+sqrt(3)-(4pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=tan(3x),\at x= pi/9

tangent of

f (x) = tan (3 x), at x = \frac{π}{9}

y = 12 x + 3 - \frac{4 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{9}, 3)

Find the slope of

f (x) = tan (3 x) : \frac{df ( x )}{d x} = sec^{2} (3 x) \cdot 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(\frac{π}{9}, 3) : y = 12 x + 3 - \frac{4 π}{3}

y = 12 x + 3 - \frac{4 π}{3}

\int 2 + 2 cos (4 x) d x

\frac{\partial}{\partial y} (\frac{x}{( x ^{2} + y ^{2} )})

\int (x^{2}) d x

\frac{d}{d x} ((2 x)^{2 x})

\frac{d}{d x} (4 x^{3} sec (7 x))

What is the tangent of f(x)=tan(3x),\at x= pi/9 ?
The tangent of f(x)=tan(3x),\at x= pi/9 is y=12x+sqrt(3)-(4pi)/3