(dy)/(dx)+5y=e^xy^{-2}

Lösung

\frac{d y}{d x} + 5 y = e^{x} y^{- 2}

y = \frac{3 3 e ^{16 x} + c _{1}}{2 3 2 e ^{5 x}}

Schritte zur Lösung

\frac{d y}{d x} + 5 y = e^{x} y^{- 2}

Solve Bernoulli ODE:

y = \frac{3 3 e ^{16 x} + c _{1}}{2 3 2 e ^{5 x}}

y = \frac{3 3 e ^{16 x} + c _{1}}{2 3 2 e ^{5 x}}

\frac{d}{d x} ((x^{2} - 2) sin (x) + 2 x cos (x))

x \to 2 lim (\frac{∣ x - 3 ∣}{x - 3})

\int tan^{3} (5 x) sec^{2} (5 x) d x

\frac{d}{d x} (\frac{1 + cos ( x )}{1 - cos ( x )})

\frac{d}{d x} (\frac{sin ( x )}{1 - cos ( x )})