tangent x^2=y^2,(1,-1)

解答

切线

x^{2} = y^{2}, (1, - 1)

y = - x

求解步骤

计算

x^{2} = y^{2}

的斜率:

\frac{d y}{d x} = \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

找到斜率 m=

- 1

且穿过

(1, - 1)

的直线:

y = - x

y = - x

t an g e n t f (x) = x^{2} - 7 x + 7, at x = 0

\frac{\partial}{\partial x} (- y \cdot cos (x))

x y^{^{'}} = (1 - 4 x^{2}) tan (y)

\int_{2}^{\infty} y e^{- 9 y} d y

\frac{d ^{2}}{d x ^{2}} ((x^{3} + 2 x)^{6})