derivative (1/(y^2)-9/(y^4))(y+7y^3)

Lösung

ableitung von

(\frac{1}{y ^{2}} - \frac{9}{y ^{4}}) (y + 7 y^{3})

\frac{62}{y ^{2}} + \frac{27}{y ^{4}} + 7

Schritte zur Lösung

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{9}{y ^{4}}) (y + 7 y^{3}))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{y ^{2}} - \frac{9}{y ^{4}}, g = y + 7 y^{3}

= \frac{d}{d y} (\frac{1}{y ^{2}} - \frac{9}{y ^{4}}) (y + 7 y^{3}) + \frac{d}{d y} (y + 7 y^{3}) (\frac{1}{y ^{2}} - \frac{9}{y ^{4}})

\frac{d}{d y} (\frac{1}{y ^{2}} - \frac{9}{y ^{4}}) = - \frac{2}{y ^{3}} + \frac{36}{y ^{5}}

\frac{d}{d y} (y + 7 y^{3}) = 1 + 21 y^{2}

= (- \frac{2}{y ^{3}} + \frac{36}{y ^{5}}) (y + 7 y^{3}) + (1 + 21 y^{2}) (\frac{1}{y ^{2}} - \frac{9}{y ^{4}})

Vereinfache

(- \frac{2}{y ^{3}} + \frac{36}{y ^{5}}) (y + 7 y^{3}) + (1 + 21 y^{2}) (\frac{1}{y ^{2}} - \frac{9}{y ^{4}}) : \frac{62}{y ^{2}} + \frac{27}{y ^{4}} + 7

= \frac{62}{y ^{2}} + \frac{27}{y ^{4}} + 7

\int - 8 sin (x) d x

\int \frac{x ^{2} - x + 8}{x ^{3} + 2 x} d x

\int (x + 1) (3 x + 2) d x

t an g e n t f (x) = x^{3} - 12 x

\int (\frac{3}{5}) cos (x) d x