What is the solution for 9(t+1)((dy)/(dt))-6y=18t ?

The solution for 9(t+1)((dy)/(dt))-6y=18t is y=6t+c_{1}(t+1)^{2/3}+9

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9(t+1)((dy)/(dt))-6y=18t

9 (t + 1) (\frac{d y}{d t}) - 6 y = 18 t

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

Solution steps

9 (t + 1) (\frac{d y}{d t}) - 6 y = 18 t

Solve linear ODE:

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

\frac{17}{x}

\frac{\partial}{\partial x} ((x - 1)^{2})

\frac{3}{( s - 7 ) ^{4}}

\int arctan (8 t) d t

\frac{\partial}{\partial x} (\frac{x}{A})

What is the solution for 9(t+1)((dy)/(dt))-6y=18t ?
The solution for 9(t+1)((dy)/(dt))-6y=18t is y=6t+c_{1}(t+1)^{2/3}+9