What is the solution for 2y^'+ty=7 ?

The solution for 2y^'+ty=7 is y=(7sqrt(pi)\erfi(t/2)}{2e^{(t^2)/4}}+(c_{1})/(e^{\frac{t^2)/4)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2y^'+ty=7

2 y^{^{'}} + t y = 7

y = \frac{7 π erfi ( \frac{t}{2} )}{2 e ^{\frac{t ^{2}}{4}}} + \frac{c _{1}}{e ^{\frac{t ^{2}}{4}}}

Solution steps

2 y^{'} (t) + t y = 7

Solve linear ODE:

y = \frac{7 π erfi ( \frac{t}{2} )}{2 e ^{\frac{t ^{2}}{4}}} + \frac{c _{1}}{e ^{\frac{t ^{2}}{4}}}

y = \frac{7 π erfi ( \frac{t}{2} )}{2 e ^{\frac{t ^{2}}{4}}} + \frac{c _{1}}{e ^{\frac{t ^{2}}{4}}}

\frac{d}{d x} (\frac{3 x - 1}{2 x + 5})

f (x) = 7^{x}

\frac{2}{3} t^{3} \cdot e^{- 8 t}

\frac{d}{d x} (\frac{4}{x ^{2}} - \frac{2}{x})

\frac{\partial}{\partial x} (3 y^{2} + 20 x^{2} y^{3})

What is the solution for 2y^'+ty=7 ?
The solution for 2y^'+ty=7 is y=(7sqrt(pi)\erfi(t/2)}{2e^{(t^2)/4}}+(c_{1})/(e^{\frac{t^2)/4)}