(dy)/(dx)=(2x+sec^2(x))/(4y)

Lösung

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{4 y}

y = \frac{x ^{2} + tan ( x ) + c _{1}}{2}, y = - \frac{x ^{2} + tan ( x ) + c _{1}}{2}

Schritte zur Lösung

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{4 y}

Solve separable ODE:

y = \frac{x ^{2} + tan ( x ) + c _{1}}{2}, y = - \frac{x ^{2} + tan ( x ) + c _{1}}{2}

y = \frac{x ^{2} + tan ( x ) + c _{1}}{2}, y = - \frac{x ^{2} + tan ( x ) + c _{1}}{2}

\frac{\partial}{\partial y} (y ln (x))

\frac{d}{d x} (40 x^{4} + 180 x^{3} + 240 x^{2} + 100 x)

\frac{d}{d x} (\frac{1}{3} (3 - 5 x)^{3})

\int_{0}^{2} \frac{16}{21 x ^{2}} d x

t an g e n t 9 x^{2}, at x = 2