y^{''}+2y^'-8y=6e-2x-e-x

Lösung

y^{^{''}} + 2 y^{^{'}} - 8 y = 6 e - 2 x - e - x

y = c_{1} e^{2 x} + c_{2} e^{- 4 x} + \frac{3 x}{8} - \frac{20 e - 3}{32}

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) - 8 y = 6 e - 2 x - e - x

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 4 x} + \frac{3 x}{8} - \frac{20 e - 3}{32}

y = c_{1} e^{2 x} + c_{2} e^{- 4 x} + \frac{3 x}{8} - \frac{20 e - 3}{32}

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