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Popular Calculus >

y^'=-y/2

Solution

y^{^{'}} = - \frac{y}{2}

Solution

y = e^{\frac{- t - c _{1}}{2}}

Solution steps

y^{'} (t) = - \frac{y}{2}

Solve separable ODE:

y = e^{\frac{- t - c _{1}}{2}}

y = e^{\frac{- t - c _{1}}{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-y/2 ?
The solution for y^'=-y/2 is y=e^{(-t-c_{1})/2}