What is the limit as h approaches 1/2 of (8h^3-1)/(1-2h) ?

The limit as h approaches 1/2 of (8h^3-1)/(1-2h) is -3

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limit as h approaches 1/2 of (8h^3-1)/(1-2h)

h \to \frac{1}{2} lim (\frac{8 h ^{3} - 1}{1 - 2 h})

- 3

Solution steps

h \to \frac{1}{2} lim (\frac{8 h ^{3} - 1}{1 - 2 h})

Simplify

\frac{8 h ^{3} - 1}{1 - 2 h} : - 4 h^{2} - 2 h - 1

= h \to \frac{1}{2} lim (- 4 h^{2} - 2 h - 1)

Plug in the value

h = \frac{1}{2}

= - 4 (\frac{1}{2})^{2} - 2 \cdot \frac{1}{2} - 1

Simplify

- 4 (\frac{1}{2})^{2} - 2 \cdot \frac{1}{2} - 1 : - 3

= - 3

What is the limit as h approaches 1/2 of (8h^3-1)/(1-2h) ?
The limit as h approaches 1/2 of (8h^3-1)/(1-2h) is -3