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Popular Calculus >

integral of cos(npi x/2)

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Solution

∫cos(nπ2x​)dx

Solution

πn2​sin(2nxπ​)+C
Solution steps
∫cos(nπ2x​)dx
Multiply nπ2x​:2πnx​
=∫cos(2πnx​)dx
Apply u-substitution
=∫πn2cos(u)​du
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=πn2​⋅∫cos(u)du
Use the common integral: ∫cos(u)du=sin(u)=πn2​sin(u)
Substitute back u=2nxπ​=πn2​sin(2nxπ​)
Add a constant to the solution=πn2​sin(2nxπ​)+C

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Frequently Asked Questions (FAQ)

  • What is the integral of cos(npi x/2) ?

    The integral of cos(npi x/2) is 2/(pin)sin((nxpi)/2)+C
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