What is the derivative of (-x^3+4x^2)^3 ?

The derivative of (-x^3+4x^2)^3 is 3(-x^3+4x^2)^2(-3x^2+8x)

What is the first derivative of (-x^3+4x^2)^3 ?

The first derivative of (-x^3+4x^2)^3 is 3(-x^3+4x^2)^2(-3x^2+8x)

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derivative of

(- x^{3} + 4 x^{2})^{3}

3 (- x^{3} + 4 x^{2})^{2} (- 3 x^{2} + 8 x)

Solution steps

\frac{d}{d x} ((- x^{3} + 4 x^{2})^{3})

Apply the chain rule:

3 (- x^{3} + 4 x^{2})^{2} \frac{d}{d x} (- x^{3} + 4 x^{2})

= 3 (- x^{3} + 4 x^{2})^{2} \frac{d}{d x} (- x^{3} + 4 x^{2})

\frac{d}{d x} (- x^{3} + 4 x^{2}) = - 3 x^{2} + 8 x

= 3 (- x^{3} + 4 x^{2})^{2} (- 3 x^{2} + 8 x)

What is the derivative of (-x^3+4x^2)^3 ?
The derivative of (-x^3+4x^2)^3 is 3(-x^3+4x^2)^2(-3x^2+8x)
What is the first derivative of (-x^3+4x^2)^3 ?
The first derivative of (-x^3+4x^2)^3 is 3(-x^3+4x^2)^2(-3x^2+8x)