What is the derivative of x^2+(128/x) ?

The derivative of x^2+(128/x) is 2x-(128)/(x^2)

What is the first derivative of x^2+(128/x) ?

The first derivative of x^2+(128/x) is 2x-(128)/(x^2)

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\frac{d}{d x} (x^{2} + \frac{128}{x})

2 x - \frac{128}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{128}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{128}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{128}{x}) = - \frac{128}{x ^{2}}

= 2 x - \frac{128}{x ^{2}}

d er i v a t i v e f (x) = sin (arccos (x))

d er i v a t i v e \frac{3600}{x}

\int_{0}^{1} \frac{7 y}{e ^{2 y}} d y

\int sin (2 x) cos (2 x) tan (2 x) d x

d er i v a t i v e 2 sin^{3} (t)

What is the derivative of x^2+(128/x) ?
The derivative of x^2+(128/x) is 2x-(128)/(x^2)
What is the first derivative of x^2+(128/x) ?
The first derivative of x^2+(128/x) is 2x-(128)/(x^2)