What is the solution for y^{''}-6y^'+13=0 ?

The solution for y^{''}-6y^'+13=0 is y=c_{1}e^{6t}+c_{2}+(13t)/6

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y^{''}-6y^'+13=0

y^{^{''}} - 6 y^{^{'}} + 13 = 0

y = c_{1} e^{6 t} + c_{2} + \frac{13 t}{6}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 13 = 0

Solve linear ODE:

y = c_{1} e^{6 t} + c_{2} + \frac{13 t}{6}

y = c_{1} e^{6 t} + c_{2} + \frac{13 t}{6}

\int \frac{37}{37 + e ^{x}} d x

f (x) = 7 ln (x)

\int cos (\frac{π x}{3}) d x

\int arctan (\frac{x}{3}) d x

y = \frac{4 x ^{2} + 6 x + 2}{x}

What is the solution for y^{''}-6y^'+13=0 ?
The solution for y^{''}-6y^'+13=0 is y=c_{1}e^{6t}+c_{2}+(13t)/6