What is the derivative of Acos(x+Bsin(x)) ?

The derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)

What is the first derivative of Acos(x+Bsin(x)) ?

The first derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)

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\frac{d}{d x} (A cos (x) + B sin (x))

- A sin (x) + B cos (x)

Solution steps

\frac{d}{d x} (A cos (x) + B sin (x))

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A cos (x)) + \frac{d}{d x} (B sin (x))

\frac{d}{d x} (A cos (x)) = - A sin (x)

\frac{d}{d x} (B sin (x)) = B cos (x)

= - A sin (x) + B cos (x)

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

a re a y = \frac{1}{2} x, y = \frac{6}{x}

\frac{d}{d x} (6 x^{5} ln (x) + x^{5})

x \to 0 lim (\frac{1 - cos ( 4 x )}{x})

\frac{d}{d x} (3 (4 e^{2 x} x + 4 e^{2 x}))

What is the derivative of Acos(x+Bsin(x)) ?
The derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)
What is the first derivative of Acos(x+Bsin(x)) ?
The first derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)