What is the derivative of sqrt(7x+9) ?

The derivative of sqrt(7x+9) is 7/(2sqrt(7x+9))

What is the first derivative of sqrt(7x+9) ?

The first derivative of sqrt(7x+9) is 7/(2sqrt(7x+9))

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\frac{d}{d x} (7 x + 9)

\frac{7}{2 7 x + 9}

Solution steps

\frac{d}{d x} (7 x + 9)

Apply the chain rule:

\frac{1}{2 7 x + 9} \frac{d}{d x} (7 x + 9)

= \frac{1}{2 7 x + 9} \frac{d}{d x} (7 x + 9)

\frac{d}{d x} (7 x + 9) = 7

= \frac{1}{2 7 x + 9} \cdot 7

Simplify

\frac{1}{2 7 x + 9} \cdot 7 : \frac{7}{2 7 x + 9}

= \frac{7}{2 7 x + 9}

d er i v a t i v e f (t) = (1 + t) (2 t^{2} - 7)

d er i v a t i v e f (x) = \frac{e ^{x^{2}}}{x ^{3}}

d er i v a t i v e f (x) = x^{3} - 12 x

\frac{d}{d z} (cos (z))

x \to 0 lim (π)

What is the derivative of sqrt(7x+9) ?
The derivative of sqrt(7x+9) is 7/(2sqrt(7x+9))
What is the first derivative of sqrt(7x+9) ?
The first derivative of sqrt(7x+9) is 7/(2sqrt(7x+9))