What is the integral of sin(t)2t ?

The integral of sin(t)2t is 2(-tcos(t)+sin(t))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sin(t)2t

\int sin (t) 2 t d t

2 (- t cos (t) + sin (t)) + C

Solution steps

\int sin (t) \cdot 2 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (t) t d t

Apply Integration By Parts

= 2 (- t cos (t) - \int - cos (t) d t)

\int - cos (t) d t = - sin (t)

= 2 (- t cos (t) - (- sin (t)))

Simplify

= 2 (- t cos (t) + sin (t))

Add a constant to the solution

= 2 (- t cos (t) + sin (t)) + C

\int \frac{sin ( 2 x )}{e ^{x}} d x

l a pl a ce t r an s f or m 2 sin (2 t)

\frac{\partial}{\partial x} (7 e^{x} cos (yz))

d er i v a t i v e x^{4} f (x)

y^{^{''}} + 4 y^{^{'}} = 6 e^{- 3 t}

What is the integral of sin(t)2t ?
The integral of sin(t)2t is 2(-tcos(t)+sin(t))+C